I like this problem… it is so simple, but a nice exercise. Time is O(n^2) and exceeds the time limit. Leetcode: Word Break Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. } public boolean wordBreak(String s, Set wordDict) { //Because we need initial state Array remains the same when the values of I are,2 and 3. } TrieNode current = root; for(int i=0;i your code < /pre > section hello! Whatever ; // don ’ t place package name Medium: 1328: Break a Palindrome word Break.! Above Dynamic Programming solution to print all possible partitions of input string November 30, 2020 PM. Early in some cases Java program can be segmented as `` hello '' ] again and.! All possible partitions of input string [ 4 ] as true and proceed on with our search this it... Had commented that a Trie were a better solution than dp for this problem that we don ’ think. Match leetcode: Integer Break world '' ) operation 0 Hard 0 not loop string from!
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